RE: Why always open array as parameter?

From: Wijck, Bart van <"Wijck,>
Date: Tue, 11 Dec 2001 15:44:44 +0100

It does, but that makes it even weirder to understand. Why does it matter if
one declares them as one specified type or as two identical types?????

regards, Bart


> From: "Wijck, Bart van" <Bart_van_Wijck{([at]})nowhere.xy
> To: "'Treutwein; Bernhard'"
<Bernhard.Treutwein{([at]})nowhere.xy
> Subject: RE: Why always open array as parameter?
> Date: Tue, 11 Dec 2001 15:25:54 +0100

> I do not know what IMHO means, but I'm not sure of your answer. Surely
it's
> the type of f (ARRAY 8 OF CHAR) which is relevant, not that it so happens
to
> be filled with 3 characters ("123"). By the way you can fill it with 7 or
8
> characters('1234567' or '12345678') but that does not matter. There is
> still a compile error. The only thing I can think of is that it's a
question
> of efficiency.
>

absolutely correct, I was too fast ...

I'm not shure about it, but

f and fid have lone ARRAY 8 OF CHAR decls.

If you change that to:

TYPE F = ARRAY 8 OF CHAR

VAR f : F;

... fid : F ...

it should work.

PS: IMHO <=> in my humble opinion.

regards


    Bernhard Treutwein
    Bernhard.Treutwein{([at]})nowhere.xy
    Tel. 049-89-2180-2774 Fax.: 089-2180-9927742
Received on Tue Dec 11 2001 - 14:44:44 UTC

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